In the diagram O is the center of the circle, ∠SOR = 64° and ∠PSO = 36°. Calculate ∠PQR
100o
96o
94o
86o
Correct answer is D
< OSR = < ORS = \(\frac{180° - 64°}{2}\) = 58°
< PSR = 36° + 58° = 94°
< PSR + < PQR = 180°
94° + < PQR = 180° \(\implies\) < PQR = 180° - 94° = 86°
Similar Questions
Find the median of 2, 1, 0, 3, 1, 1, 4, 0, 1 and 2 ...
The nth term of a sequence is given by 2\(^{2n - 1}\). Find the sum of the first four terms....
In the diagram, CDE is a triangle, ABEF is cyclic quadrilateral, AB||CD, ∠BAF = 65o and ∠AFE = 8...
The difference between the length and width of a rectangle is 6cm and the area is 135cm². What ...
Evaluate: 16\(^{0.16}\) × 16\(^{0.04}\) × 2\(^{0.2}\)...
If \(\frac{1+\sqrt{2}}{1-\sqrt{2}}\) is expressed in the form of x+y√2 find the values of ...
Solve the equation log8x - 4log8x = 2...
If a binary operation * is defined by x * y = x + 2y, find 2 * (3 * 4)...