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Three consecutive terms of a geometric progression are gi...

Three consecutive terms of a geometric progression are given as n-2, n and n+3. Find the common ratio

A.

1/4

B.

1/2

C.

2/3

D.

3/2

Correct answer is D

r=\frac{n}{n-2}\hspace{1mm}and\hspace{1mm}r=\frac{n+3}{n}\\∴\frac{n}{n-2}=\frac{n+3}{n}\\n^2 = n^2 +3n - 2n-6\\0=n-6\\∴n=6\\But\hspace{1mm}r = \frac{n}{n-2}\\r=\frac{6}{6-2}\\\frac{6}{4}=\frac{3}{2}