In the diagram, XYZ is an equilateral triangle of side 6cm and Y is the midpoint of \(\overline{XY}\). Find tan (< XZT)
\(\frac{1}{\sqrt{3}}\)
\(\frac{\sqrt{3}}{2}\)
\(\sqrt{3}\)
\(\frac{1}{2}\)
Correct answer is A
ZT = \(\sqrt{6^2 - 3^2}\)
ZT = \(\sqrt{27}\) = \(3\sqrt{3}\)
tan (< XZT) = \(\frac{3}{3\sqrt{3}}\)
= - \(\frac{1}{\sqrt{3}}\)
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