6
116
114
53
Correct answer is B
h:x→2−12x−3
h(x)=2(2x−3)−12x−3=4x−72x−3
Let x = h(y)
x=4y−72y−3
x(2y−3)=4y−7⟹2xy−4y=3x−7
y=3x−72x−4
h−1(x)=3x−72x−4
∴
= \frac{\frac{-11}{2}}{-3} = \frac{11}{6}
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