\(\frac{25}{4} - m\)
\(\frac{25}{4} - 2m\)
\(\frac{25}{4} + m\)
\(\frac{25}{4} + 2m\)
Correct answer is A
\(2x^{2} - 5x + m = 0\)
\(a = 2, b = -5, c = m\)
\(\alpha + \beta = \frac{-b}{a} = \frac{5}{2}\)
\(\alpha \beta = \frac{c}{a} = \frac{m}{2}\)
\(\alpha^{2} + \beta^{2} = (\alpha + \beta)^{2} - 2\alpha\beta\)
= \((\frac{5}{2})^{2} - 2(\frac{m}{2}) \)
= \(\frac{25}{4} - m\)