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Find the locus of points which is equidistant from P(4, 5...

Find the locus of points which is equidistant from P(4, 5) and Q(-6, -1).

A.

3x - 5y + 13 = 0

B.

3x - 5y - 7 = 0

C.

5x - 3y + 7 = 0

D.

5x + 3y - 1 = 0

Correct answer is D

Midpoint between P(4, 5) and Q(-6, -1) = 462,512=(1,2)

Gradient of PQ = 5(1)4(6)=35

Gradient of line perpendicular to PQ = 135=53

line=y2x+1=53

3y6=5x5

5x+3y6+5=05x+3y1=0