In the diagram, a ladder PS leaning against a vertical wall PR makes angle x° with the horizontal floor. The ladder slides down to a point QT such that angle QTR = 30° and SNT = y°. Find an expression for tan y.
\(\frac{\sqrt{3} \tan x - 1}{\sqrt{3} + \tan x}\)
\(\frac{\sqrt{3} \tan x}{\sqrt{3} + \tan x}\)
\(\frac{\sqrt{3} \tan x + 1}{\sqrt{3} - \tan x}\)
\(\frac{3 \tan x - 1}{\sqrt{3} - \tan x}\)
Correct answer is A
No explanation has been provided for this answer.