\(26 ms^{-2}\)
\(18 ms^{-2}\)
\(17 ms^{-2}\)
\(16 ms^{-2}\)
Correct answer is D
\(v(t) = 3t^{2} - 2t + 1\)
\(\frac{\mathrm d v}{\mathrm d t} = a(t) = 6t - 2\)
\(a(3) = 6(3) - 2 = 18 - 2 = 16 ms^{-2}\)
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