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The velocity of a body of mass 4.56 kg increases from \((10 ...

The velocity of a body of mass 4.56 kg increases from (10ms1,060o)to(50ms1,060o) in 16 seconds . Calculate the magnitude of force acting on it.

A.

17.1 N

B.

11.4 N

C.

36.5 N

D.

5.7 N

Correct answer is B

m=4.56kg;t=16s;v1=(10ms1,060o);v2=(50ms1,060o)

Notice that there is no change in the direction of the velocity

So,we don't need to write it in a vector form

a=\frac{∆v}{t}=\frac{50 - 10}{16}

a=\frac{40}{16}=2.5ms^{-2}

F = ma = 4.56 x 2.5

∴ F = 11.4 N