-1
0
\(2a^{3} - \frac{2}{a^{3}}\)
\(\frac{2}{a^{3}} - 2a^{3}\)
Correct answer is C
\(h(x) = x^{3} - \frac{1}{x^{3}}\)
\(h(a) = a^{3} - \frac{1}{a^{3}}\)
\(h(\frac{1}{a}) = (\frac{1}{a})^{3} - \frac{1}{(\frac{1}{a})^{3}} = \frac{1}{a^{3}} - a^{3}\)
\(h(a) - h(\frac{1}{a}) = (a^{3} - \frac{1}{a^{3}}) - (\frac{1}{a^{3}} - a^{3}) = 2a^{3} - \frac{2}{a^{3}}\)