-1
0
2a3−2a3
2a3−2a3
Correct answer is C
h(x)=x3−1x3
h(a)=a3−1a3
h(1a)=(1a)3−1(1a)3=1a3−a3
h(a)−h(1a)=(a3−1a3)−(1a3−a3)=2a3−2a3
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