A basket contains 3 red and 1 white identical balls. A ball is drawn from the basket at random. Calculate the probability that it is either white or red.
\(\frac{1}{3}\)
\(\frac{1}{2}\)
\(\frac{3}{4}\)
1
Correct answer is D
P(white or red) = P(white) + P(red)
= \(\frac{3}{4} + \frac{1}{4}\)
= 1