8
7
6
5
Correct answer is A
\(^{n}C_{3} = \frac{n!}{(n - 3)! 3!}\)
\(^{n}P_{2} = \frac{n!}{(n - 2)!}\)
\(\frac{^{n}C_{3}}{^{n}P_{2}} = \frac{n!}{(n - 3)! 3!} ÷ \frac{n!}{(n - 2)!}\)
\(\frac{n!}{(n - 3)! 3!} \times \frac{(n - 2)!}{n!} = \frac{(n - 2)!}{(n - 3)! 3!}\)
Note that \((n - 2)! = (n - 2) \times (n - 2 - 1)! = (n - 2)(n - 3)!\)
\(\frac{(n - 2)(n - 3)!}{(n - 3)! 3!} = 1\)
\(\frac{n - 2}{3!} = 1 \implies n - 2 = 6\)
\(n = 2 + 6 = 8\)
(\(\frac{3√6}{√5} + \frac{√54}{3√5}\))\(^{-1}\)...
Rationalize; \(\frac{1}{\sqrt{2 + 1}}\)...
Given that \(a = i - 3j\) and \(b = -2i + 5j\) and \(c = 3i - j\), calculate \(|a - b + c|\)....
Find the remainder when \(5x^{3} + 2x^{2} - 7x - 5\) is divided by (x - 2)....
Marks 5 - 7 8 - 10 11 - 13 14 - 16 17 - 19 20 - 22 Frequency 4 7 26 41 1...