3
2
34
-3
Correct answer is D
g(x)=x+1x+2,x≠2
Let y = x, then g(y)=y+1y+2
Let x = g(y), so that x=y+1y+2
x(y+2)=y+1
xy+2x=y+1⟹xy−y=1−2x
y(x−1)=1−2x⟹y=1−2xx−1
y=g−1(x)=1−2xx−1
g−1(2)=1−2(2)2−1=−3
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