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Differentiate x2+xy5=0...

Differentiate x2+xy5=0

A.

(2x+y)x

B.

(2xy)x

C.

x2x+y

D.

(2x+y)x

Correct answer is A

ddx(x2+xy5)=d(x2)dx+d(xy)dxd(5)dx=0

= 2x+xdydx+y=0

xdydx=(2x+y)

dydx=(2x+y)x