−(2x+y)x
(2x−y)x
−x2x+y
(2x+y)x
Correct answer is A
ddx(x2+xy−5)=d(x2)dx+d(xy)dx−d(5)dx=0
= 2x+xdydx+y=0
⟹xdydx=−(2x+y)
dydx=−(2x+y)x
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