4√2
6√2
2√10
4√10
Correct answer is C
BC=BA+AC
Given, AB, then BA=−AB
= AB=(43)⟹BA=(−4−3)
∴
= \begin{pmatrix} -2 \\ -6 \end{pmatrix}
|BC| = \sqrt{(-2)^{2} + (-6)^{2}} = \sqrt{40}
= 2\sqrt{10}
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