-1
\frac{-1}{7}
\frac{1}{7}
1
Correct answer is A
\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12} = \frac{3 + 3}{3^{2} - 3 - 12}
= \frac{6}{-6} = -1
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