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Find lim...

Find \lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12}

A.

-1

B.

\frac{-1}{7}

C.

\frac{1}{7}

D.

1

Correct answer is A

\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12} = \frac{3 + 3}{3^{2} - 3 - 12}

= \frac{6}{-6} = -1