8
6
5
4
Correct answer is C
(x∗y)=x+y2
(3∗b)=3+b2
x∘y=x2y
(3+b2)∘48=(3+b2)248=13
(3+b)248×4=13
(3+b)2=48×43=64
b2+6b+9=64⟹b2+6b+9−64=0
b2+6b−55=0⟹b2−5b+11b−55=0
b(b−5)+11(b−5)=0⟹(b−5)=0 or (b+11)=0
Since b > 0, b - 5 = 0
b = 5.
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