y≥1x
y≤1x
y≤1x2
y≥1x2
Correct answer is D
log10y+3log10x≥log10x
⟹log10y≥log10x−3log10x
log10y≥−2log10x=log10y≥log10x−2
log10y≥log10(1x2)⟹y≥1x2
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