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The velocity, V, of a particle after t seconds, is \(V = 3t^...

The velocity, V, of a particle after t seconds, is V=3t2+2t1. Find the acceleration of the particle after 2 seconds.

A.

10ms2

B.

12ms2

C.

14ms2

D.

17ms2

Correct answer is C

accl=dVdt

V=3t2+2t1

a \text{(after 2 seconds)} = (6\times 2) + 2 = 12+2 = 14ms^{-2}