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Given that f(x)=3x212x+12 and \(f(x) = 3...

Given that f(x)=3x212x+12 and f(x)=3, find the values of x.

A.

1, 3

B.

-1, -3

C.

1, -3

D.

-1, 3

Correct answer is A

f(x)=3x212x+12 and f(x)=3

3x^{2} - 12x + 9 = 0; 3x^{2} - 9x - 3x + 9 = 0

3x(x - 3) - 3(x - 3) = (3x - 3)(x - 3) = 0

3x - 3 = 0 or x - 3 = 0

x = 1 or 3