Each exterior angle of a polygon is 30o. Calculate the sum of the interior angles.... Question 23893

Each exterior angle of a polygon is 30^o. Calculate the sum of the interior angles

540^o

720^o

1080^o

1800^o

Correct answer is D

number of sides = \(\frac{360^o}{\theta} = \frac{360^o}{306o}\)

n = 12^o

Sum of interior angle = (n - 2) 180^o

(12 - 2) 180v = 10 x 180^o

= 1800^o

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