\(\frac{8!}{2!}\)
\(\frac{8!}{3! 2!}\)
\(\frac{8!}{2! 2! 2!}\)
8!
Correct answer is C
MACICITA is an eight letter word = 8!
Since we have repeating letters, we have to divide to remove duplicates accordingly. There are 2A, 2C, 2I
∴ \(\frac{8!}{2! 2! 2!}\)