\(\frac{2}{3}\)
\(\frac{4}{5}\)
\(\frac{2}{5}\)
\(\frac{1}{2}\)
Correct answer is D
The outcomes are {HHH, HHT, HTT, HTH, THH, THT, TTH, TTT}
P(at least two heads) = \(\frac{4}{8}\)
= \(\frac{1}{2}\)
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