In the diagram above, l1 is parallel to l2, Find the value of < PMT
A.
82o
B.
36o
C.
72o
D.
118o
Correct answer is A
< MPT = 180o - 118o = 62o
< PML = 62o ( Alternative angle)
y + 2y + 10o + 62o = 180o (Angles on a straight line)
3y = 180 - 72
\(\frac{3y}{3}\) = \(\frac{108}{3}\)
y = 36o
< PMT = 2y + 10 = 2(36) + 10 = 82o