10001\(_{two}\)
10011\(_{two}\)
10111\(_{two}\)
11111\(_{two}\)
111111\(_{two}\)
Correct answer is D
11101\(_{two}\) → 29
+ 10011\(_{two}\) → 19
- 10001\(_{two}\) → 17
11111 = 31
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