H varies directly as p and inversely as the square of y. ...
H varies directly as p and inversely as the square of y. If H = 1, p = 8 and y = 2, find H in terms of p and y.
H = p4y2
H = 2py2
H = p2y2
H = py2
Correct answer is C
H ∝ py2
H = pky2
1 = 8k22
k = 48
= 12
H = p2y2
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