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In ∆ PQR, P\hat{Q}P = 84^°, |Q\hat{P}R |= 43^° and |...

In ∆ PQR, P\hat{Q}P = 84^°, |Q\hat{P}R |= 43^° and |PQ| = 5cm. Find /QR/ in cm, correct to 1 decimal place.

A.

3.4

B.

4.3

C.

5.9

D.

6.2

Correct answer is B

Using the sine rule
\frac{|QR|}{sinP}=\frac{|PQ|}{sinR}\\ \frac{x}{sin43^o}=\frac{5}{sin53^o}\\ x = \frac{5\times sin43^o}{sin53^o}\\ =\frac{5\times 0.6820}{0.7986}\\ =4.3