N132.50K
N136.30K
N125.40K
N257.42K
Correct answer is B
\( A = P \left(1 + \frac{r}{100}\right)^n \)
Where P = 126, r = 4,n = 2
A=126 \( \left(1 + \frac{4}{100}\right)^2 \text{Using LCM} \)
=126 \( \left(\frac{100+4}{100}\right)^2 = 126 \left(\frac{104}{100}\right)^2 \)
=126 \( \left(1.04^2 \right) \)
= 126 * 1.04 * 1.04
=136.28
A = 136.30 (approx.)
The Amount A, = N136.30k