Find the value of k if \(\frac{k}{\sqrt{3} + \sqrt{2}}\) = k\(\sqrt{3 - 2}\)

A.

3

B.

2

C.

\(\sqrt{3}\)

D.

\(\sqrt 2\)

Correct answer is D

\(\frac{k}{\sqrt{3} + \sqrt{2}}\) = k\(\sqrt{3 - 2}\)

\(\frac{k}{\sqrt{3} + \sqrt{2}}\) x \(\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}}\)

= k\(\sqrt{3 - 2}\)

= k(\(\sqrt{3} - \sqrt{2}\))

= k\(\sqrt{3 - 2}\)

= k\(\sqrt{3}\) - k\(\sqrt{2}\)

= k\(\sqrt{3 - 2}\)

k2 = \(\sqrt{2}\)

k = \(\frac{2}{\sqrt{2}}\)

= \(\sqrt{2}\)