In the diagram above O is the center of the circle, if ∠PAQ = 75o, what is the value of ∠PBQ?
A.
15o
B.
75o
C.
105o
D.
150o
E.
210o
Correct answer is C
< PBQ = 180° - 75° (opp angles of a cyclic quadrilateral)
= 105°