In the diagram above, AB//CD, the bisector of ∠BAC and ∠ACD meet at E. Find the value of ∠AEC
A.
30o
B.
45o
C.
60o
D.
75o
E.
90o
Correct answer is E
Ae is a bisector of BAC => EAC = 45o
CE is the bisector of ACD => ACE = 45o
AEC = 180o - [EAC + ACE]
= 180o - (45o + 45o) = 180o - 90o = 90o