y = 2x
y = x + 1
y = x
y = 12x+1
Correct answer is D
y = mx + c; when x = 0; y = 1
1 = m(0) + c; 1 = 0 + c; c = 1
when x = 2; y = 2
2 = m(2) + c; 2 = 2m + c; but c = 1
2 = 2m + 1
2 - 1 = 2m
2m = 1
m = 12
y = 12x + 1
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