$\begin{array}{c|c} x & 0 & 2 & 4 & 6\\ \hline y & 1 & 2 & 3 & 4\end{array}$ .
The table is for the relation y = mx + c where m and c are constants. What is the equation of the line described in the tablet?

y = 2x

y = x + 1

y = x

y = $\frac{1}{2}x + 1$

Correct answer is D

y = mx + c; when x = 0; y = 1

1 = m(0) + c; 1 = 0 + c; c = 1

when x = 2; y = 2

2 = m(2) + c; 2 = 2m + c; but c = 1

2 = 2m + 1

2 - 1 = 2m

2m = 1

m = $\frac{1}{2}$

y = $\frac{1}{2}$ x + 1

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