1−cosxsinx
1 - cos x
sin x
1 + cos x
1+cosxsinx
Correct answer is A
√1−cosx1+cosx = a
a2 = 1−cosx1+cosx
1−cosx1+cosx = 1−cosx1−cosx
= (1−cosx)2cos2x
a2 = (1−cosx)2sin2x
a = 1−cosxsinx
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