32
33
35
3
Correct answer is D
3−5n91−n×27n+1
3−5n32(1−n)×33(n+1)
3−5n÷32(1−n)×33(n+1)
3−5n−2(1−n)+3(n+1)
3−5n−2+2n+3n+3
3−5n+5n+3−2
31
= 3
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