If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log (\(\frac{28}{3}\))

A.

2x + y - z

B.

2x + z - y

C.

x + y - 2x

D.

x + x - y

View answer & explanation

Correct answer is B

log (\(\frac{28}{3}) = \log (\frac{7 \times 4}{3})\)

= log 7 + log 4 - log 3

log 7 + log 22 - log 3 = log 7 + 2 - log 3

= z + 2x - y

= 2x + z - y

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