Given that x = 2 and y = - $\frac{1}{4}$ , evaluate $\frac{x^2y - 2xy}{5}$

zero

$\frac{1}{5}$

Correct answer is A

Given; x = 2; y = $\frac{-1}{4}$

= $\frac{x^2y - 2xy}{5}$

= $\frac{2^2(\frac{-1}{4}) - 2(2)(\frac{-1}{4})}{5}$

= $\frac{4(\frac{-1}{4}) + 4(\frac{-1}{4})}{5}$

= $\frac{1 + 1}{5}$

= $\frac{0}{5}$

= 0

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Given that x = 2 and y = - $\frac{1}{4}$ , evaluate $\frac{x^2y - 2xy}{5}$