Evaluate \(\frac{2\sin 30 + 5\tan 60}{\sin 60}\), leaving your answer in surd form.

A.

\(\frac{2\sqrt{3}}{3} + 10\)

B.

\(\frac{3\sqrt{2} - 1}{5}\)

C.

\(\frac{3\sqrt{2} + 1}{5}\)

D.

\(\frac{2\sqrt{3}}{3} - 10\)

Correct answer is A

\(\frac{2\sin 30 + 5\tan 60}{\sin 60}\)

\(\sin 30 = \frac{1}{2}; \tan 60 = \sqrt{3}; \sin 60 = \frac{\sqrt{3}}{2}\)

\(\therefore \frac{2\sin 30 + 5\tan 60}{\sin 60} = \frac{2(\frac{1}{2}) + 5(\sqrt{3})}{\frac{\sqrt{3}}{2}}\)\)

= \(\frac{1 + 5\sqrt{3}}{\frac{\sqrt{3}}{2}}\)

= \(\frac{2(1 + 5\sqrt{3})}{\sqrt{3}}\)

= \(\frac{2 + 10\sqrt{3}}{\sqrt{3}}\)

Rationalizing, we get

= \(\frac{2\sqrt{3} + 30}{3}\)

= \(\frac{2}{3} \sqrt{3} + 10\)