\(\frac{1}{x + y}\)
\(\frac{1}{xy}\)
x + y
xy
Correct answer is B
\(\frac{\frac{1}{x} + \frac{1}{y}}{x + y}\) = \(\frac{\frac{y + x}{xy}}{x + y}\) = \(\frac{x + y}{xy}\) = \(\frac{x + y}{xy} \times \frac{1}{x + y}\) = \(\frac{1}{xy}\)
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