4
5
6
7
Correct answer is C
23\(_y\) = 1111\(_{\text{two}}\),
2 x y\(^1\) + 3 x y\(^0\) = 1 x 2\(^3\) + 1 x 2\(^1\) + 1 x 2\(^o\)
2y + 3 = 8 + 4 + 2 + 1
2y + 3 = 15
\(\frac{2y}{2}\)
\(\frac{12}{2}\)
y = 6
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