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If p = [ $\frac{Q(R - T)}{15}$ ] $^ \frac{1}{3}$ , make T th...

If p = [ $\frac{Q(R - T)}{15}$ ] $^ \frac{1}{3}$ , make T the subject of the relation

A.

T = R + $\frac{P^3}{15Q}$

B.

T = R - $\frac{15P^3}{Q}$

C.

T = R + $\frac{P^3}{15Q}$

D.

T = 15R - $\frac{Q}{P^3}$

View answer & explanation

Correct answer is B

Cubic both sides; P³ = $\frac{Q(R - T)}{15}$

(cross multiplication) Q(R - T) = 15P³

(divide both sides by Q); R - T = 15 $\frac{1}{Q}$

(subtract r from both sides) - T = $\frac{15P^3}{Q - R}$

T = R - $\frac{15P^3}{Q}$

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