In a committee of 5, which must be selected from 4 males ...
In a committee of 5, which must be selected from 4 males and 3 females. In how many ways can the members be chosen if it were to include 2 females?
144 ways
15 ways
185 ways
12 ways
Correct answer is D
For the committee to include 2 females, we must have 3 males, so that there should be 5 members.
That is, \(^4C_3 \times ^3C_2\)
= \(\frac{4!}{(4 - 3)! 3!} \times \frac{3!}{(3 - 2)! 2!}\)
= 4 × 3 = 12 ways
Calculate the perimeter of a sector of a circle of raduis 12cm and angle 60o. ...
If \(y = x(x^4 + x + 1)\), evaluate \(\int \limits_{0} ^{1} y \mathrm d x\)....
If 92x = \(\frac{1}{3}\)(27x), find x...
If gt2 - k - w = 0, make g the subject of the formula...
PQRSTW is a regular hexagon and QS intersects RT at V. Calculate ∠TVS ...
Simplify without using tables \(\frac{log_26}{log_28}\) - \(\frac{log_23}{2log_2\frac{1}{2}}\)...
In the diagram, PQR is a tangent to the circle QST at Q. If |QT| = |ST| and ∠SQR = 68°, find...