In a committee of 5, which must be selected from 4 males ...
In a committee of 5, which must be selected from 4 males and 3 females. In how many ways can the members be chosen if it were to include 2 females?
144 ways
15 ways
185 ways
12 ways
Correct answer is D
For the committee to include 2 females, we must have 3 males, so that there should be 5 members.
That is, 4C3×3C2
= 4!(4−3)!3!×3!(3−2)!2!
= 4 × 3 = 12 ways
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