In the figure, PS = RS = QS and QRS = 50°. Find QPR
In the figure, PS = RS = QS and QRS = 50°. Find QPR
25O
40O
50O
65O
Correct answer is A
In the figure PS = RS = QS, they will have equal base QR = RP
In angle SQR, angle S = 50O
In angle QRP, 65 + 65 = 130O
Since RQP = angle RPQ = \(\frac{180 - 130}{2}\)
= \(\frac{50}{2} = 25^o\)
QPR = 25°
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