Two angles of a triangle are 45º each and its longest side is 12cm. Find the length of one of the other sides
12cm
9\(\sqrt{2}\)cm
6\(\sqrt{2}\)cm
6cm
3\(\sqrt{2}\)cm
Correct answer is C
Two angles of a triangle are 45º each and its longest side is 12cm, this simply describes an isosceles triangle
two equal angles and two equal sides
using Pythagoras theorem,
\(x^2 + x^2 = 12^2\)
\(2x^2\) = 144
\(x^2\) = 72( after dividing b/sides by 2)
x = \(\sqrt{72} = 6\sqrt{2}\)cm.