In the fiqure where PQRTU is a circle, ISTI = IRSI and angle...
In the fiqure where PQRTU is a circle, ISTI = IRSI and angle TSR = 52o. Find the angle marked m
A.
128o
B.
52o
C.
104o
D.
64o
E.
116o
Correct answer is E
< STR = \(\frac{180 - 52}{2}\) = \(\frac{128}{2}\) = 64o
< PTR = 180 - < STR(angle on a straight line)
= 180 - 64 = 116o
< PQR + < PTR = 180(Supplementary)
< PQR + 118 = 180
< PQR = 180 - 118
= 64
M = 180 - < PQR
= 180 - < PQR = 180 - 64
= 116o
Similar Questions
If a \(\ast\) b = + \(\sqrt{ab}\), evaluate 2 \(\ast\)(12 \(\ast\) 27)...
In the figure, find angle x ...
In triangles XYZ and XQP, XP = 4cm, XQ = 5cm and PQ = QY = 3cm. Find ZY ...
By how much is the mean of 30, 56, 31, 55, 43 and 44 less than the median? ...
Evaluate \(\int^{1}_{-2}(x-1)^{2}dx\) ...
Find the radius of a sphere whose surface area is 154 cm\(^2\)? ...