128o
52o
104o
64o
116o
Correct answer is E
< STR = 180−522 = 1282 = 64o
< PTR = 180 - < STR(angle on a straight line)
= 180 - 64 = 116o
< PQR + < PTR = 180(Supplementary)
< PQR + 118 = 180
< PQR = 180 - 118
= 64
M = 180 - < PQR
= 180 - < PQR = 180 - 64
= 116o
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