A student sitting on a tower 68 metres high observes his principal's car at the angle of depression of 20°. How far is the car from the bottom of the tower to the nearest metre?
184m
185m
186m
187m
Correct answer is D
Tan 20° = \(\frac{68m}{x}\)
x tan 20° = 68
x = \(\frac{68}{tan 20}\) = \(\frac{68}{0.364}\)
x = 186.8
= 187m