\(\frac{1}{36}\)
\(\frac{1}{18}\)
\(\frac{1}{13}\)
\(\frac{1}{6}\)
\(\frac{1}{3}\)
Correct answer is A
\((216^{\frac{1}{3}})^{-2}\)
= \(216^{\frac{-2}{3}}\)
= (3√216)\(^{-2}\)
= (6)\(^{-2}\)
= \(\frac{1}{6^2}\)
=\(\frac{1}{36}\)
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