In the figure, PS = SR and Rx is a tangent to the circle at R, < QRX is equal to 72o. Find angle SPR
A.
20o
B.
36o
C.
72o
D.
30o
E.
15o
Correct answer is B
XRQ = RSQ (Alternate segment)
s = 72o
(80o - 72o = 180o)
a + b + c = 190o = 2b + c = 180o
2b + 108 = 180o
2b = 72o
b = 36o