\(\frac{b(a-x+1)}{a+1}\)
\(\frac{a+1}{b(a-x+1)}\)
\(\frac{a(b-x+1)}{b+1}\)
\(\frac{b}{a(b-x+1)}\)
Correct answer is A
If \(\frac{bx+y(a+1)}{b(a+1)}=1\\ bx + ya + y = ba + b; y(a+1) = ba+b-bx\\ y(a+1)=b(a+1-x); y = \frac{b(1+a-x}{a+1}\)
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