b(a−x+1)a+1
a+1b(a−x+1)
a(b−x+1)b+1
ba(b−x+1)
Correct answer is A
If bx+y(a+1)b(a+1)=1bx+ya+y=ba+b;y(a+1)=ba+b−bxy(a+1)=b(a+1−x);y=b(1+a−xa+1
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