In the figures, PQ is a tangent to the circle at R and UT is parallel to PQ. if < TRQ = x^o, find < URT in terms of x

2x^o

(90 - x)^o

(90 + x)^o

(180 - 2x)^o

Correct answer is D

< URT = < TRQ (angle alternate a tangent and a chord equal to angle in the alternate segment)

< RUT = x^o

In \(\bigtriangleup\) URT

< RUT + < RUT + < UTR = 180^o (sum of int. < s of \(\bigtriangleup\))

< URT + x + x = 180^o

< URT = 180^o - 2x

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In the figures, PQ is a tangent to the circle at R and UT is parallel to PQ. if < TRQ = xo, find < URT in terms of x

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In the figures, PQ is a tangent to the circle at R and UT is parallel to PQ. if < TRQ = x^o, find < URT in terms of x