A body of mass 6kg rests on an inclined plane. The normal reaction is R and the limiting frictional force is F as shown in the image above. if F = 30N, and g = 10ms2 then the angle of inclination \( \theta \) is
\( 15^{\circ} \)
\( 30^{\circ} \)
\( 45^{\circ} \)
\( 60^{\circ} \)
\( 75^{\circ} \)
Correct answer is B
No explanation has been provided for this answer.