$A body of mass 6kg rests on an inclined plane. The normal reaction is R and the limiting frictional force is F as shown in the image above. if F = 30N, and g = 10ms2 then the angle of inclination $ \theta $ is$

A body of mass 6kg rests on an inclined plane. The normal reaction is R and the limiting frictional force is F as shown in the image above. if F = 30N, and g = 10ms2 then the angle of inclination $\theta$ is

$15^{\circ}$

$30^{\circ}$

$45^{\circ}$

$60^{\circ}$

$75^{\circ}$

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Correct answer is B

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A body of mass 6kg rests on an inclined plane. The normal reaction is R and the limiting frictional force is F as shown in the image above. if F = 30N, and g = 10ms2 then the angle of inclination $\theta$ is

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A body of mass 6kg rests on an inclined plane. The normal reaction is R and the limiting frictional force is F as shown in the image above. if F = 30N, and g = 10ms2 then the angle of inclination θ \theta is

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A body of mass 6kg rests on an inclined plane. The normal reaction is R and the limiting frictional force is F as shown in the image above. if F = 30N, and g = 10ms2 then the angle of inclination $\theta$ is